在基于范围的 for 循环内从容器中删除元素 [英] Erasing an element from a container while inside a range-based for loop

问题描述

我想从当前在基于范围的 for 循环中使用的容器中删除一个元素.这会导致未定义的行为吗?或者，如果我没有调用 erase()，erase() 之后 element 的下一个值会是下一个元素应该是什么?

I want to erase an element from a container which is being currently used within a ranged-based for loop. Will this cause undefined behaviour? Or will the next value of element after erase() be what the next element is supposed to be if I didn't call erase()?

示例:

std::map<int, int> someMap;
/* Fill in someMap */
for (auto& element : someMap)
{
    /* ... */
    if ( /* Some condition */ )
        someMap.erase(element.first);
}

推荐答案

这应该是一个未定义的行为.因为根据 14882/2011，基于范围的 for 语句等效于:

It should be a undefined behavior. Because according to 14882/2011 the range-based for statement is equivalent to:

auto && __range = range-init;
for ( auto __begin = begin-expr(__range),
   __end = end-expr(__range);
   __begin != __end;
   ++__begin ) {
   for-range-declaration = *__begin;
   statement
}

这篇关于在基于范围的 for 循环内从容器中删除元素的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！