Matplotlib 散点图；颜色作为第三个变量的函数 [英] Matplotlib scatterplot; color as a function of a third variable

问题描述

我想制作一个散点图(使用 matplotlib)，其中根据第三个变量对点进行着色.我对此非常了解:

I want to make a scatterplot (using matplotlib) where the points are shaded according to a third variable. I've got very close with this:

plt.scatter(w, M, c=p, marker='s')

其中 w 和 M 是数据点，p 是我想要着色的变量.
但是我想用灰度而不是彩色来做.有人可以帮忙吗?

where w and M are the data points and p is the variable I want to shade with respect to.
However I want to do it in greyscale rather than colour. Can anyone help?

推荐答案

无需手动设置颜色.相反，指定灰度颜色图...

There's no need to manually set the colors. Instead, specify a grayscale colormap...

import numpy as np
import matplotlib.pyplot as plt

# Generate data...
x = np.random.random(10)
y = np.random.random(10)

# Plot...
plt.scatter(x, y, c=y, s=500)
plt.gray()

plt.show()

或者，如果您更喜欢更广泛的颜色图，您也可以指定 cmap kwarg 到 scatter.要使用其中任何一个的反向版本，只需指定其中任何一个的_r"版本.例如.gray_r 而不是 gray.有几种不同的预制灰度颜色图(例如 gray、gist_yarg、binary 等).

Or, if you'd prefer a wider range of colormaps, you can also specify the cmap kwarg to scatter. To use the reversed version of any of these, just specify the "_r" version of any of them. E.g. gray_r instead of gray. There are several different grayscale colormaps pre-made (e.g. gray, gist_yarg, binary, etc).

import matplotlib.pyplot as plt
import numpy as np

# Generate data...
x = np.random.random(10)
y = np.random.random(10)

plt.scatter(x, y, c=y, s=500, cmap='gray')
plt.show()

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