Python matplotlib 限制为整数刻度位置 [英] Python matplotlib restrict to integer tick locations
本文介绍了Python matplotlib 限制为整数刻度位置的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我经常想制作计数条形图.如果计数很低,我经常会得到不是整数的主要和/或次要刻度位置.我怎样才能防止这种情况?当数据是计数时,在 1.5 处打勾是没有意义的.
Quite often I want to make a bar chart of counts. If the counts are low I often get major and/or minor tick locations that are not integers. How can I prevent this? It makes no sense to have a tick at 1.5 when the data are counts.
这是我的第一次尝试:
import pylab
pylab.figure()
ax = pylab.subplot(2, 2, 1)
pylab.bar(range(1,4), range(1,4), align='center')
major_tick_locs = ax.yaxis.get_majorticklocs()
if len(major_tick_locs) < 2 or major_tick_locs[1] - major_tick_locs[0] < 1:
ax.yaxis.set_major_locator(pylab.MultipleLocator(1))
minor_tick_locs = ax.yaxis.get_minorticklocs()
if len(minor_tick_locs) < 2 or minor_tick_locs[1] - minor_tick_locs[0] < 1:
ax.yaxis.set_minor_locator(pylab.MultipleLocator(1))
当计数很小时工作正常,但当计数很大时,我会得到很多小滴答:
which works OK when the counts are small but when they are large, I get many many minor ticks:
import pylab
ax = pylab.subplot(2, 2, 2)
pylab.bar(range(1,4), range(100,400,100), align='center')
major_tick_locs = ax.yaxis.get_majorticklocs()
if len(major_tick_locs) < 2 or major_tick_locs[1] - major_tick_locs[0] < 1:
ax.yaxis.set_major_locator(pylab.MultipleLocator(1))
minor_tick_locs = ax.yaxis.get_minorticklocs()
if len(minor_tick_locs) < 2 or minor_tick_locs[1] - minor_tick_locs[0] < 1:
ax.yaxis.set_minor_locator(pylab.MultipleLocator(1))
如何从第一个示例中获得所需的行为,同时避免在第二个示例中发生的情况?
How can I get the desired behaviour from the first example with small counts whilst avoiding what happens in the second?
推荐答案
您可以使用 MaxNLocator
方法,如下所示:
You can use the MaxNLocator
method, like so:
from pylab import MaxNLocator
ya = axes.get_yaxis()
ya.set_major_locator(MaxNLocator(integer=True))
这篇关于Python matplotlib 限制为整数刻度位置的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文