无法通过脚本更改游戏对象颜色? [英] Can't change GameObject color via script?
问题描述
我有一个用于 UI 的画布,图像与画布大小相同.Image
的 rgba
为 0,0,0,0
,使其不可见(因为 a
是0).我想让图像从脚本中淡入黑色.这是我正在使用的代码:
I have a canvas for UI, with an image the same size of the canvas. The Image
has an rgba
of 0,0,0,0
, making it invisible (because the a
is 0). I want to have the image fade into black from a script. Here is the code I am using:
public class NavigationC : MonoBehaviour {
public Image screen;
float fadeTime = 3f;
Color colorToFadeTo;
void StartGame()
{
colorToFadeTo = new Color(0f, 0f, 0f, 255f);
screen.CrossFadeColor(colorToFadeTo, fadeTime, true, true);
}
}
现在,这在执行时不会做任何事情.但是,当我统一手动更改图像的 a
值以使图像可见时,我可以看到脚本更改了图像的颜色.所以脚本确实有效,它只是不可见,因为 a
值没有被脚本改变.那么如何让图像从不可见变为黑色?
Now, this doesn't do anything when executed. But when I change the image's a
value manually in unity so that the image becomes visible, I can see the script changing the image's color. So the script does work, it just isn't visible because the a
value is not being changed by the script.
So how can I make the image fade from invisible to black?
推荐答案
这是你的问题:
新颜色(0f, 0f, 0f, **255f**);
Color
构造函数参数采用从 0f
到 1f
的值,但您将 0f
传递给 255f
范围值.
The Color
constructor parameter takes values from 0f
to 1f
but you are passing 0f
to 255f
range value to it.
应该是:
colorToFadeTo = new Color(0f, 0f, 0f, 1f);
如果你想使用0
到255
的范围,那么你必须除以255
.
If you want to use the 0
to 255
range then you must divide it by 255
.
colorToFadeTo = new Color(0f, 0f, 0f, 255f/255f);
<小时>
此外,还有 Color32
可以取 0
和 255
之间的值.您可以使用它,然后将其变回颜色.
Also, there is Color32
which can take values between 0
and 255
. You can use that then covert it back to color.
Color32 color32 = new Color32(0f, 0f, 0f, 255f));
Color color = color32;
这篇关于无法通过脚本更改游戏对象颜色?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!