仅当 value 为 true 时才返回对象键 [英] Return an object key only if value is true

问题描述

如何仅在对象键名称为真时才返回对象键名称?

How do i return an object key name only if the value of it is true?

我正在使用下划线，我唯一看到的是如何轻松返回键，我想尽可能避免重复迭代:

I'm using underscore and the only thing i see is how to return keys which is easy, i want to avoid redundant iterations as much as possible:

示例:

Object {1001: true, 1002: false} 

我想要一个只有 1001 的数组...

I want an array with only 1001 in it...

推荐答案

Object.keys 从对象中获取密钥，然后你可以过滤基于值的键

Object.keys gets the keys from the object, then you can filter the keys based on the values

var obj = {1001: true, 1002: false};

var keys = Object.keys(obj);

var filtered = keys.filter(function(key) {
    return obj[key]
});

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