为什么我的比较在 Java 中的 char 和 int 之间不起作用? [英] Why doesn't my compare work between char and int in Java?

问题描述

char c = '0';
int i = 0;
System.out.println(c == i);

为什么这总是返回 false?

Why does this always returns false?

推荐答案

虽然这个问题很不清楚，但我很确定发帖人想知道为什么会打印false:

Although this question is very unclear, I am pretty sure the poster wants to know why this prints false:

char c = '0';
int i = 0;
System.out.println(c == i);

答案是因为每个可打印的字符都分配了一个唯一的代码编号，这就是 char 在被视为 int 时所具有的值.字符0的码号是十进制的48，显然48不等于0.

The answer is because every printable character is assigned a unique code number, and that's the value that a char has when treated as an int. The code number for the character 0 is decimal 48, and obviously 48 is not equal to 0.

为什么数字的字符代码不等于数字本身?主要是因为前几个代码，尤其是 0，太特殊了，不能用于如此平凡的目的.

Why aren't the character codes for the digits equal to the digits themselves? Mostly because the first few codes, especially 0, are too special to be used for such a mundane purpose.

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