太多的“if"语句? [英] Too many 'if' statements?

问题描述

以下代码确实按照我的需要工作，但它很丑陋、过多或其他一些事情.我查看了公式并尝试编写一些解决方案，但最终得到的语句数量相似.

The following code does work how I need it to, but it's ugly, excessive or a number of other things. I've looked at formulas and attempted to write a few solutions, but I end up with a similar amount of statements.

在这种情况下，是否有一种数学公式可以使我受益，或者如果陈述可以接受，则为 16?

Is there a type of math formula that would benefit me in this instance or are 16 if statements acceptable?

为了解释代码，它是针对一种同时回合制的游戏.两个玩家每个都有四个动作按钮，结果来自一个数组 (0-3)，但变量 'one' &如果有帮助，可以为两个"分配任何内容.结果是，0 = 都不赢，1 = p1 赢，2 = p2 赢，3 = 都赢.

To explain the code, it's for a kind of simultaneous-turn-based game.. two players have four action buttons each and the results come from an array (0-3), but the variables 'one' & 'two' can be assigned anything if this helps. The result is, 0 = neither win, 1 = p1 wins, 2 = p2 wins, 3 = both win.

public int fightMath(int one, int two) {

    if(one == 0 && two == 0) { result = 0; }
    else if(one == 0 && two == 1) { result = 0; }
    else if(one == 0 && two == 2) { result = 1; }
    else if(one == 0 && two == 3) { result = 2; }
    else if(one == 1 && two == 0) { result = 0; }
    else if(one == 1 && two == 1) { result = 0; }
    else if(one == 1 && two == 2) { result = 2; }
    else if(one == 1 && two == 3) { result = 1; }
    else if(one == 2 && two == 0) { result = 2; }
    else if(one == 2 && two == 1) { result = 1; }
    else if(one == 2 && two == 2) { result = 3; }
    else if(one == 2 && two == 3) { result = 3; }
    else if(one == 3 && two == 0) { result = 1; }
    else if(one == 3 && two == 1) { result = 2; }
    else if(one == 3 && two == 2) { result = 3; }
    else if(one == 3 && two == 3) { result = 3; }

    return result;
}

推荐答案

如果你不能想出一个公式，你可以使用一个表格来计算这样有限数量的结果:

If you cannot come up with a formula, you can use a table for such a limited number of outcomes:

final int[][] result = new int[][] {
  { 0, 0, 1, 2 },
  { 0, 0, 2, 1 },
  { 2, 1, 3, 3 },
  { 1, 2, 3, 3 }
};
return result[one][two];

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