根据一个字段值过滤 elasticsearch 结果以仅包含唯一文档 [英] Filter elasticsearch results to contain only unique documents based on one field value

问题描述

我的所有文档都有一个 uid 字段，其中包含一个将文档链接到用户的 ID.有多个文档具有相同的 uid.

All my documents have a uid field with an ID that links the document to a user. There are multiple documents with the same uid.

我想对所有文档执行搜索，只返回每个唯一 uid 得分最高的文档.

I want to perform a search over all the documents returning only the highest scoring document per unique uid.

选择相关文档的查询是一个简单的multi_match查询.

The query selecting the relevant documents is a simple multi_match query.

推荐答案

您需要一个 top_hits 聚合.

You need a top_hits aggregation.

对于您的具体情况:

{
  "query": {
    "multi_match": {
      ...
    }
  },
  "aggs": {
    "top-uids": {
      "terms": {
        "field": "uid"
      },
      "aggs": {
        "top_uids_hits": {
          "top_hits": {
            "sort": [
              {
                "_score": {
                  "order": "desc"
                }
              }
            ],
            "size": 1
          }
        }
      }
    }
  }
}

上面的查询确实执行您的 multi_match 查询并根据 uid 聚合结果.对于每个 uid 存储桶，它只返回一个结果，但是在存储桶中的所有文档都根据 _score 按降序排序之后.

The query above does perform your multi_match query and aggregates the results based on uid. For each uid bucket it returns only one result, but after all the documents in the bucket were sorted based on _score in descendant order.

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