从变量中批量提取路径和文件名 [英] Batch Extract path and filename from a variable

问题描述

如何从变量中提取路径和文件名?

How can I extract path and filename from a variable?

Setlocal EnableDelayedExpansion
set file=C:Usersl72rugschiriDesktopfs.cfg

我想在不使用任何函数或任何 GOTO 的情况下做到这一点.有可能吗?

I want to do that without using any function or any GOTO. is it possible?

推荐答案

@ECHO OFF
SETLOCAL
set file=C:Usersl72rugschiriDesktopfs.cfg
FOR %%i IN ("%file%") DO (
ECHO filedrive=%%~di
ECHO filepath=%%~pi
ECHO filename=%%~ni
ECHO fileextension=%%~xi
)

不真的确定没有功能"是什么意思

Not really sure what you mean by no "function"

显然，将 ECHO 更改为 SET 以设置变量而不是 ECHO...

Obviously, change ECHO to SET to set the variables rather thon ECHOing them...

请参阅 for 文档 获取完整列表.

See for documentation for a full list.

ceztko 的测试用例(供参考)

ceztko's test case (for reference)

@ECHO OFF
SETLOCAL
set file="C:Users l72rugschiriDesktopfs.cfg"
FOR /F "delims=" %%i IN ("%file%") DO (
ECHO filedrive=%%~di
ECHO filepath=%%~pi
ECHO filename=%%~ni
ECHO fileextension=%%~xi
)

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