从变量批量提取路径和文件名 [英] Batch Extract path and filename from a variable

问题描述

我

如何解压路径和文件名从变量？

  SETLOCAL EnableDelayedExpansion
设置文件= C：\\用户\\ l72rugschiri \\桌面\\ fs.cfg
 

我想这样做，不使用任何功能或任何GOTO。
这可能吗？

解决方案

  @ECHO OFF
SETLOCAL
设置文件= C：\\用户\\ l72rugschiri \\桌面\\ fs.cfg
FOR %% I IN（％文件％）DO（
ECHO filedrive = %%〜迪
ECHO文件路径= %%〜PI
ECHO文件名= %%〜に
ECHO fileextension = %%〜喜
）
 

未真正相信你绝不功能是什么意思

显然，改变 ECHO 到 SET 来设置变量，而马拉松附和他们......

请参阅http://www.microsoft.com/resources/documentation/windows/xp/all/proddocs/en-us/percent.mspx一个完整的清单。

How can I extract path and filename from a variable?

Setlocal EnableDelayedExpansion
set file=C:\Users\l72rugschiri\Desktop\fs.cfg

I want to do that without using any function or any GOTO. is it possible?

解决方案

@ECHO OFF
SETLOCAL
set file=C:\Users\l72rugschiri\Desktop\fs.cfg
FOR %%i IN ("%file%") DO (
ECHO filedrive=%%~di
ECHO filepath=%%~pi
ECHO filename=%%~ni
ECHO fileextension=%%~xi
)

Not really sure what you mean by no "function"

Obviously, change ECHO to SET to set the variables rather thon ECHOing them...

See http://www.microsoft.com/resources/documentation/windows/xp/all/proddocs/en-us/percent.mspx for a full list.

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