复制文件列表 (txt) [英] Copy a list (txt) of files

问题描述

我在 SO 上看过一些脚本示例，但似乎没有一个提供如何从 .t​​xt 列表中读取文件名的示例.

I've seen some scripts examples over SO, but none of them seems to provide examples of how to read filenames from a .txt list.

这个例子很好，把A文件夹中的所有文件复制到B文件夹

This example is good, so as to copy all files from A to B folder

xcopy c:olddir*.java c:
ewdir /D /E /Q /Y

但我需要像下一个这样的东西，我可以在其中填充源文件夹和目标文件夹:

But I need something like the next, where I can fill actually the source and destination folder:

 @echo off
 set src_folder = c:whatever*.*
 set dst_folder = c:foo
 xcopy /S/E/U %src_folder% %dst_folder%

而不是 src_folder = c:whatever*.*，那些 *.* 需要是从 txt 文件中读取的文件列表.

And instead of src_folder = c:whatever*.*, those *.* need to be list of files read from a txt file.

文件列表.txt(示例)

File-list.txt (example)

file1.pds
filex.pbd
blah1.xls

有人可以建议我怎么做吗?

Could someone suggest me how to do it?

推荐答案

给定名为 File-list.txt 的文件中的文件名列表，以下几行应该满足您的要求:

Given your list of file names in a file called File-list.txt, the following lines should do what you want:

@echo off
set src_folder=c:whatever
set dst_folder=c:	arget
for /f "tokens=*" %%i in (File-list.txt) DO (
    xcopy /S/E "%src_folder%\%%i" "%dst_folder%"
)

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