批处理：复制文件列表（TXT） [英] Batch: Copy a list (txt) of files

问题描述

我已经看到了SO一些脚本的例子，但其中没有人似乎提供了如何从.txt列表读取文件名的例子。

I've seen some scripts examples over SO, but noone of them seems to provide examples of how to read filenames from a .txt list.

这个例子是好的，但是从A所有文件到B文件夹复制

This example is good, but to copy all files from A from to B folder

xcopy c:\olddir\*.java c:\newdir /D /E /Q /Y

不过，我需要像旁边，在那里我可以填写实际的源和目标文件夹：

But I need something like the next, where I can fill actually the source and destination folder:

 @echo off
 set src_folder = c:\whatever\*.*
 set dst_folder = c:\foo
 xcopy /S/E/U %src_folder% %dst_folder%

和代替 SRC_FOLDER = C：\\什么\\ *。* ，这些 * 需。文件列表要从一个txt文件readden。

And instead of src_folder = c:\whatever\*.*, those *.* need to be list of files readden from a txt file.

文件的LIST.TXT（例如）

File-list.txt (example)

file1.pds
filex.pbd
blah1.xls

可能有人建议我该怎么办呢？

Could someone suggest me how to do it?

推荐答案

鉴于你在一个名为文件-LIST.TXT 文件名列表，下面的行应做你想做的：

Given your list of file names in a file called File-list.txt, the following lines should do what you want:

@echo off
set src_folder=c:\whatever
set dst_folder=c:\target
for /f "tokens=*" %%i in (File-list.txt) DO (
    xcopy /S/E/U "%src_folder%\%%i" "%dst_folder%"
)

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