传递给函数的原始变量名? [英] original variable name passed to function?

问题描述

可能的重复:
PHP:获取作为参数传递的变量名称
如何在PHP?

如果我有

$abc = '123';

function write($var){

}

我如何在 write 中发现现在由 $var 表示的变量被称为 $abc?

How would I inside write find out that the variable now represented by $var was called $abc?

推荐答案

这是不可能的.即使传递引用也无济于事.您必须将名称作为第二个参数传递.

It's not possible. Even pass-by-reference won't help you. You'll have to pass the name as a second argument.

但是您所问的问题绝对不能很好地解决您的问题.

But what you have asked is most assuredly not a good solution to your problem.

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