如何获取传递给函数的变量的原始变量名称 [英] How to get the original variable name of variable passed to a function

问题描述

是否有可能获得传递给函数的变量的原始变量名？例如

Is it possible to get the original variable name of a variable passed to a function? E.g.

foobar = "foo"

def func(var):
    print var.origname

因此：

So that:

func(foobar)

返回：

>> foobar

编辑：

所有我试图做的功能都是：

All I was trying to do was make a function like:

def log(soup):
    f = open(varname+'.html', 'w')
    print >>f, soup.prettify()
    f.close()

..并让该函数根据传递给它的变量的名称生成文件名。

.. and have the function generate the filename from the name of the variable passed to it.

我想如果这是不可能的，我只需要将变量和变量的名称作为一个字符串传递给每一个。

I suppose if it's not possible I'll just have to pass the variable and the variable's name as a string each time.

推荐答案

你不能。它在被传递给函数之前被评估。您只需将其作为字符串传递即可。

You can't. It's evaluated before being passed to the function. All you can do is pass it as a string.

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