如何在文件查找中使用正则表达式 [英] How to use regex in file find

问题描述

我试图查找所有日期和 3 天或更长时间前的文件.

I was trying to find all files dated and all files 3 days or more ago.

find /home/test -name 'test.log.d{4}-d{2}-d{2}.zip' -mtime 3

它没有列出任何东西.有什么问题吗?

It is not listing anything. What is wrong with it?

推荐答案

find /home/test -regextype posix-extended -regex '^.*test.log.[0-9]{4}-[0-9]{2}-[0-9]{2}.zip' -mtime +3

1. -name 使用 globular 表达式，又名通配符.你想要的是-regex
2. 要按照您的意图使用间隔，您需要告诉 find 使用 Extended正则表达式通过-regextype posix-extended 标志
3. 你需要避开句号因为在正则表达式中，一个时期有任何单个的特殊含义字符.你想要的是一个用 .
表示的文字句点
4. 只匹配那些大于超过 3 天，您需要在您的号码前加上 + 作为前缀在 -mtime +3 中.

1. -name uses globular expressions, aka wildcards. What you want is -regex
2. To use intervals as you intend, you need to tell find to use Extended Regular Expressions via the -regextype posix-extended flag
3. You need to escape out the periods because in regex a period has the special meaning of any single character. What you want is a literal period denoted by .
4. To match only those files that are greater than 3 days old, you need to prefix your number with a + as in -mtime +3.

概念证明

$ find . -regextype posix-extended -regex '^.*test.log.[0-9]{4}-[0-9]{2}-[0-9]{2}.zip'
./test.log.1234-12-12.zip

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