如何在Java中使用正则表达式查找重复的字符？ [英] How can I find repeated characters with a regex in Java?

问题描述

任何人都可以给我一个Java正则表达式来识别字符串中的重复字符吗？我只是寻找立即重复的字符，它们可以是字母或数字。

Can anyone give me a Java regex to identify repeated characters in a string? I am only looking for characters that are repeated immediately and they can be letters or digits.

abccde< - 寻找这个（立即重复c）

abccde <- looking for this (immediately repeating c's)

abcdce< - 不是这个（c被另一个字符分开）

abcdce <- not this (c's seperated by another character)

推荐答案

尝试（\\w）\\1 +

\\\\ 匹配任何单词字符（字母，数字或下划线）和 \\1 + 匹配第一组括号中的任何内容，一次或多次。所以你最终匹配任何出现的单词字符，然后立即再跟一个或多个相同的单词字符。

The \\w matches any word character (letter, digit, or underscore) and the \\1+ matches whatever was in the first set of parentheses, one or more times. So you wind up matching any occurrence of a word character, followed immediately by one or more of the same word character again.

（注意我把正则表达式作为Java字符串，即反斜杠已经翻了一倍）

(Note that I gave the regex as a Java string, i.e. with the backslashes already doubled for you)

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