正则表达式查找重复数字 [英] Regex to find repeating numbers

问题描述

谁能帮助我或指导我构建一个正则表达式来验证重复数字

Can anyone help me or direct me to build a regex to validate repeating numbers

例如:11111111、2222、99999999999等

eg : 11111111, 2222, 99999999999, etc

它应该验证任何长度.

推荐答案

\b(\d)\1+\b

说明:

\b   # match word boundary
(\d) # match digit remember it
\1+  # match one or more instances of the previously matched digit
\b   # match word boundary

如果 1 也应该是有效匹配(零重复)，请使用 * 而不是 +.

If 1 should also be a valid match (zero repetitions), use a * instead of the +.

如果你还想允许更长的重复(123123123)使用

If you also want to allow longer repeats (123123123) use

\b(\d+)\1+\b

如果应该将正则表达式应用于整个字符串(而不是在更长的字符串中查找重复数字")，请使用行首和行尾锚点而不是 \b:

If the regex should be applied to the entire string (as opposed to finding "repeat-numbers in a longer string), use start- and end-of-line anchors instead of \b:

^(\d)\1+$

如何匹配完全相反，我.e.并非所有数字都相同的数字(除非整个数字只是一个数字):

How to match the exact opposite, i. e. a number where not all digits are the same (except if the entire number is simply a digit):

^(\d)(?!\1+$)\d*$

^     # Start of string
(\d)  # Match a digit
(?!   # Assert that the following doesn't match:
 \1+  # one or more repetitions of the previously matched digit
 $    # until the end of the string
)     # End of lookahead assertion
\d*   # Match zero or more digits
$     # until the end of the string

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