如何正确嵌套 Bash 反引号 [英] How to properly nest Bash backticks

问题描述

要么我错过了一些强烈反对，要么反对似乎不适用于过多的程序员引用循环.

Either I missed some backlash or backlashing does not seem to work with too much programmer-quote-looping.

$ echo "hello1-`echo hello2-`echo hello3-`echo hello4```"

hello1-hello2-hello3-echo hello4

通缉

hello1-hello2-hello3-hello4-hello5-hello6-...

推荐答案

使用 $(commands) 代替:

$ echo "hello1-$(echo hello2-$(echo hello3-$(echo hello4)))"
hello1-hello2-hello3-hello4

$(commands) 与反引号的作用相同，但您可以嵌套它们.

$(commands) does the same thing as backticks, but you can nest them.

您可能还对 Bash 范围扩展感兴趣:

You may also be interested in Bash range expansions:

echo hello{1..10}
hello1 hello2 hello3 hello4 hello5 hello6 hello7 hello8 hello9 hello10

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