PHP cURL HTTP CODE 返回 0 [英] PHP cURL HTTP CODE return 0
问题描述
我不明白当我回显 $httpCode 时我总是得到 0,当我将 $html_brand 更改为损坏的 url 时,我期待 404.有什么我想念或不知道的吗?谢谢.
I dont understand when I echo $httpCode I always get 0, I was expecting 404 when I change $html_brand into a broken url. Is there anything that I miss or do not know of? Thanks.
//check if url exist
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $html_brand);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
$response = curl_exec($ch);
$httpCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
if ($httpCode == 404) {
echo "The Web Page Cannot Be Found";
return;
}
curl_close($ch);
推荐答案
如果你连接到服务器,那么你可以从它那里得到一个返回码,否则它会失败并且你得到一个 0.所以如果你尝试连接到www.google.com/lksdfk",你会得到一个 400 的返回码,如果你直接去 google.com,你会得到 302(如果你转发到下一页,然后是 200......我这样做是因为它转发到 google.com.br,所以你可能不会得到它),如果你去googlecom"你会得到一个 0(找不到主机),所以最后一个,没有人可以发回代码.
If you connect with the server, then you can get a return code from it, otherwise it will fail and you get a 0. So if you try to connect to "www.google.com/lksdfk" you will get a return code of 400, if you go directly to google.com, you will get 302 (and then 200 if you forward to the next page... well I do because it forwards to google.com.br, so you might not get that), and if you go to "googlecom" you will get a 0 (host no found), so with the last one, there is nobody to send a code back.
使用以下代码进行测试.
Tested using the code below.
<?php
$html_brand = "www.google.com";
$ch = curl_init();
$options = array(
CURLOPT_URL => $html_brand,
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HEADER => true,
CURLOPT_FOLLOWLOCATION => true,
CURLOPT_ENCODING => "",
CURLOPT_AUTOREFERER => true,
CURLOPT_CONNECTTIMEOUT => 120,
CURLOPT_TIMEOUT => 120,
CURLOPT_MAXREDIRS => 10,
);
curl_setopt_array( $ch, $options );
$response = curl_exec($ch);
$httpCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
if ( $httpCode != 200 ){
echo "Return code is {$httpCode}
"
.curl_error($ch);
} else {
echo "<pre>".htmlspecialchars($response)."</pre>";
}
curl_close($ch);
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