在数字字符串中插入逗号 [英] Insert commas into number string
问题描述
嘿,我正在尝试对字符串执行反向正则表达式搜索,以将其分成 3 位数字组.据我从 AS3 文档,在 reg ex 引擎中无法向后搜索.
Hey there, I'm trying to perform a backwards regular expression search on a string to divide it into groups of 3 digits. As far as i can see from the AS3 documentation, searching backwards is not possible in the reg ex engine.
这个练习的重点是在一个数字中插入三元组逗号,如下所示:
The point of this exercise is to insert triplet commas into a number like so:
10000000 => 10,000,000
我正在考虑这样做:
string.replace(/(d{3})/g, ",$1")
但这是不正确的,因为搜索不是从后面发生的,替换 $1 只适用于第一场比赛.
But this is not correct due to the search not happening from the back and the replace $1 will only work for the first match.
我感觉最好使用循环来执行此任务.
I'm getting the feeling I would be better off performing this task using a loop.
更新:
由于 AS3 不支持前瞻,我就是这样解决的.
Due to AS3 not supporting lookahead this is how I have solved it.
public static function formatNumber(number:Number):String
{
var numString:String = number.toString()
var result:String = ''
while (numString.length > 3)
{
var chunk:String = numString.substr(-3)
numString = numString.substr(0, numString.length - 3)
result = ',' + chunk + result
}
if (numString.length > 0)
{
result = numString + result
}
return result
}
推荐答案
如果您的语言支持正向前瞻断言,那么我认为以下正则表达式会起作用:
If your language supports postive lookahead assertions, then I think the following regex will work:
(d)(?=(d{3})+$)
用 Java 演示:
import static org.junit.Assert.assertEquals;
import org.junit.Test;
public class CommifyTest {
@Test
public void testCommify() {
String num0 = "1";
String num1 = "123456";
String num2 = "1234567";
String num3 = "12345678";
String num4 = "123456789";
String regex = "(\d)(?=(\d{3})+$)";
assertEquals("1", num0.replaceAll(regex, "$1,"));
assertEquals("123,456", num1.replaceAll(regex, "$1,"));
assertEquals("1,234,567", num2.replaceAll(regex, "$1,"));
assertEquals("12,345,678", num3.replaceAll(regex, "$1,"));
assertEquals("123,456,789", num4.replaceAll(regex, "$1,"));
}
}
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