从 NSMutableArray 中删除对象 [英] Removing object from NSMutableArray

问题描述

我在设置 for 循环时偶然发现了以下快捷方式(与我一直使用的教科书示例相比的快捷方式):

I stumbled across the following shortcut in setting up a for loop (shortcut compared to the textbook examples I have been using):

for (Item *i in items){ ... }

与较长的格式相反:

for (NSInteger i = 0; i < [items count]; i++){ ... } //think that's right

如果我使用较短的版本，有没有办法删除当前正在迭代的项目(即i")?还是我需要使用更长的格式?

If I'm using the shorter version, is there a way to remove the item currently being iterated over (ie 'i')? Or do I need to use the longer format?

推荐答案

快速枚举它:

枚举是安全的"——枚举器有一个突变守卫，所以如果你尝试修改集合在枚举期间，一个例外是提升.

numeration is "safe"—the enumerator has a mutation guard so that if you attempt to modify the collection during enumeration, an exception is raised.

无论如何，您为什么需要在枚举容器时更改容器?考虑存储需要删除的元素，并使用 removeObjectsInArray: 或 removeObjectsAtIndexes: 方法将它们从容器中删除.

Anyway why do you need to change you container while enumerating it? Consider storing elements that need to be deleted and remove them from your container using removeObjectsInArray: or removeObjectsAtIndexes: method.

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