PyQt 连接到 KeyPressEvent [英] PyQt Connect to KeyPressEvent

问题描述

某些小部件将允许我执行以下操作:

Certain widgets will allow me to do:

self.widget.clicked.connect(on_click)

但是在做:

self.widget.keyPressEvent.connect(on_key)

将失败说对象没有属性connect".

will fail saying that the object has no attribute 'connect'.

我知道对小部件进行子类化并重新实现 keyPressEvent 方法将使我能够响应事件.但是我怎样才能.connect() 到键盘事件之后，或者说，从用户上下文?

I know that sub-classing the widget and re-implementing the keyPressEvent method will allow me to respond to the event. But how can I .connect() to the keyboard event thereafter, or otherwise said, from a user context?

推荐答案

创建自定义信号，并从重新实现的事件处理程序中发出它:

Create a custom signal, and emit it from your reimplemented event handler:

class MyWidget(QtGui.QWidget):
    keyPressed = QtCore.pyqtSignal(int)

    def keyPressEvent(self, event):
        super(MyWidget, self).keyPressEvent(event)
        self.keyPressed.emit(event.key())
...

def on_key(key):
    # test for a specific key
    if key == QtCore.Qt.Key_Return:
        print('return key pressed')
    else:
        print('key pressed: %i' % key)

self.widget.keyPressed.connect(on_key)

(注意:为了保持现有的事件处理，需要调用基类实现).

(NB: calling the base-class implementation is required in order to keep the existing handling of events).

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