Java中的正弦波声音发生器 [英] Sine Wave Sound Generator in Java
问题描述
在 Java 中以任何频率生成正弦波声音的最简单方法是什么?超过 2 个字节的样本大小会有所帮助,但这并不重要.
What's the simplest way to generate a sine wave sound at any frequency in Java? A sample size more than 2 bytes would help, but it doesn't really matter.
推荐答案
参见 Beeper
一个独立的例子.
See Beeper
for a self-contained example.
也许更简单的事情?
如链接答案顶部所示的那 51 行代码片段(在下面重复 - 为单行和行内注释隔开),就像生成一个音调一样简单(好吧,你可以去掉5+ 线用于谐波).
That 51 lines of snippet (repeated below - spaced out for single line & in-line comments) as shown at the top of the linked answer, is about as simple as generating a tone gets (OK, you can take out 5+ lines for the harmonic).
人们似乎认为它应该是工具包中内置的一种方法来产生纯音.不是,需要一点点计算才能制作.
People seem to assume it should be a method built into the toolkit to produce a pure tone. It is not, and takes a little calculating to make one.
/** Generates a tone, and assigns it to the Clip. */
public void generateTone()
throws LineUnavailableException {
if ( clip!=null ) {
clip.stop();
clip.close();
} else {
clip = AudioSystem.getClip();
}
boolean addHarmonic = harmonic.isSelected();
int intSR = ((Integer)sampleRate.getSelectedItem()).intValue();
int intFPW = framesPerWavelength.getValue();
float sampleRate = (float)intSR;
// oddly, the sound does not loop well for less than
// around 5 or so, wavelengths
int wavelengths = 20;
byte[] buf = new byte[2*intFPW*wavelengths];
AudioFormat af = new AudioFormat(
sampleRate,
8, // sample size in bits
2, // channels
true, // signed
false // bigendian
);
int maxVol = 127;
for(int i=0; i<intFPW*wavelengths; i++){
double angle = ((float)(i*2)/((float)intFPW))*(Math.PI);
buf[i*2]=getByteValue(angle);
if(addHarmonic) {
buf[(i*2)+1]=getByteValue(2*angle);
} else {
buf[(i*2)+1] = buf[i*2];
}
}
try {
byte[] b = buf;
AudioInputStream ais = new AudioInputStream(
new ByteArrayInputStream(b),
af,
buf.length/2 );
clip.open( ais );
} catch(Exception e) {
e.printStackTrace();
}
}
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