将字符串解析为 int 向量 [英] parse string to vector of int

问题描述

我有一个字符串，其中包含一些用空格分隔的整数.例如

I have a string which contains some number of integers which are delimited with spaces. For example

string myString = "10 15 20 23";

我想将其转换为整数向量.所以在这个例子中，向量应该是相等的

I want to convert it to a vector of integers. So in the example the vector should be equal

vector<int> myNumbers = {10, 15, 20, 23};

我该怎么做?抱歉问了一个愚蠢的问题.

How can I do it? Sorry for stupid question.

推荐答案

您可以使用 std::stringstream.除了其他包含之外，您还需要 #include .

You can use std::stringstream. You will need to #include <sstream> apart from other includes.

#include <sstream>
#include <vector>
#include <string>

std::string myString = "10 15 20 23";
std::stringstream iss( myString );

int number;
std::vector<int> myNumbers;
while ( iss >> number )
  myNumbers.push_back( number );

这篇关于将字符串解析为 int 向量的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！