动态网址 ->Rails 中路由的控制器映射 [英] Dynamic URL -> Controller mapping for routes in Rails

问题描述

我希望能够根据我的数据库中的信息动态地将 URL 映射到控制器.

I would like to be able to map URLs to Controllers dynamically based on information in my database.

我希望做一些功能上与此等效的事情(假设使用 View 模型):

I'm looking to do something functionally equivalent to this (assuming a View model):

map.route '/:view_name',
    :controller => lambda { View.find_by_name(params[:view_name]).controller }

其他人建议动态重建路线，但这对我不起作用，因为可能有数千个视图映射到同一个控制器

Others have suggested dynamically rebuilding the routes, but this won't work for me as there may be thousands of Views that map to the same Controller

推荐答案

这个问题很老了，但我发现它很有趣.可以在 Rails 3 中使用路由器的功能来创建一个完整的解决方案来路由到 Rack 端点.

This question is old, but I found it interesting. A fully working solution can be created in Rails 3 using router's capability to route to a Rack endpoint.

创建以下 Rack 类:

Create the following Rack class:

    class MyRouter
      def call(env)
        # Matched from routes, you can access all matched parameters
        view_name= env['action_dispatch.request.path_parameters'][:view_name]

        # Compute these the way you like, possibly using view_name
        controller= 'post' 
        my_action= 'show'

        controller_class= (controller + '_controller').camelize.constantize
        controller_class.action(my_action.to_sym).call(env)
      end
    end

在路线中

    match '/:view_name', :to => MyRouter.new, :via => :get

提示来自 http://guides.rubyonrails.org/routing.html#routing-to-rack-applications 说好奇的是，'posts#index' 实际上扩展到 PostsController.action(:index)，它返回一个有效的 Rack 应用程序."

Hint picked up from http://guides.rubyonrails.org/routing.html#routing-to-rack-applications which says "For the curious, 'posts#index' actually expands out to PostsController.action(:index), which returns a valid Rack application."

在 Rails 3.2.13 中测试的变体.

A variant tested in Rails 3.2.13.

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