如何将域名后的所有内容都变成字符串 [英] How to get everything after the domain name into a string

问题描述

我的目标是将域名后的所有内容都变成一个字符串.就像在 mysite.com/page/page2 中一样，会产生一个字符串page/page2".我可以做到，但是它开始给我带来问题，例如，当站点位于子文件夹中而不是根目录中时，站点所在的文件夹也将包含在字符串中，如果我不使用 mod_rewrite获得漂亮的链接，它还会将 index.php 添加到字符串中.

因此，我需要一两个技巧来让脚本了解该站点是否位于诸如 mysite.com/sitefolder/page/page2 之类的子文件夹中，并且它仍然会产生一个字符串

page/page2

如果站点没有使用mod_rewrite并且url是mysite.com/sitefolder/index.php/page/page2，它仍然会产生一个字符串

page/page2

请记住，我在配置文件中定义了 URL 和 USE_MOD_REWRITE，所以不需要魔法.我只是不知道如何获取该字符串.我知道我可以执行 $_SERVER['REQUEST_URI'] 来获取字符串，但是 index.php 仍然会在其中.如果我解释得不够好，我很抱歉，但感谢所有帮助.

解决方案

• 解析请求uri获取路径
• 从字符串的末尾删除最终的脚本名称(例如 index.php)

• 删除任何尾部斜杠

  <前>$request = parse_url($_SERVER['REQUEST_URI']);$path = $request["path"];$result = rtrim(str_replace(basename($_SERVER['SCRIPT_NAME']), '', $path), '/');

编辑

$request = parse_url($_SERVER['REQUEST_URI']);$path = $request["path"];$result = trim(str_replace(basename($_SERVER['SCRIPT_NAME']), '', $path), '/');$result =explode('/', $result);$max_level = 2;而 ($max_level < count($result)) {未设置($result[0])；}$result = '/'.implode('/', $result);

My goal is to get everything after the domain name into a string. As in mysite.com/page/page2 would result in a string "page/page2". That I can do, however it starts giving me problems when, for example, the site is in a subfolder and not in root, then the folder the site is in will also be included in the string and if I'm not using mod_rewrite to get pretty links, it will also add index.php to the string.

So, I would need a trick or two to make the script understand whether or not the site is in a subfolder such as mysite.com/sitefolder/page/page2 and that it would still result in a string

page/page2

If the site doesn not use mod_rewrite and the url is mysite.com/sitefolder/index.php/page/page2, it would still result in a string

page/page2

Keep in mind that I have URL and USE_MOD_REWRITE defined in a config file, so no need for magic. I just have no idea how to go about getting that string. I know I could do $_SERVER['REQUEST_URI'] to get the string, but then index.php would still be in it. I'm sorry if I didn't explain well enough, but all help is appreciated.

解决方案

• get the path by parsing the request uri
• remove eventual script name from the end of the string (e.g. index.php)

• rtrim any trailing slashes

  $request = parse_url($_SERVER['REQUEST_URI']);
  $path = $request["path"];
  $result = rtrim(str_replace(basename($_SERVER['SCRIPT_NAME']), '', $path), '/');
  

EDIT

$request = parse_url($_SERVER['REQUEST_URI']);
$path = $request["path"];

$result = trim(str_replace(basename($_SERVER['SCRIPT_NAME']), '', $path), '/');

$result = explode('/', $result);
$max_level = 2;
while ($max_level < count($result)) {
    unset($result[0]);
}
$result = '/'.implode('/', $result);

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