在获取之前在 C. Scanf 中输入.问题 [英] Input in C. Scanf before gets. Problem

问题描述

我对 C 很陌生，我在向程序输入数据时遇到了问题.

I'm pretty new to C, and I have a problem with inputing data to the program.

我的代码:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(void) {
   int a;
   char b[20];

   printf("Input your ID: ");
   scanf("%d", &a);

   printf("Input your name: ");
   gets(b);   

   printf("---------");

   printf("Name: %s", b);   

   system("pause");
   return 0;
}

它允许输入 ID，但它只是跳过输入的其余部分.如果我像这样更改顺序:

It allows to input ID, but it just skips the rest of the input. If I change the order like this:

printf("Input your name: ");
   gets(b);   

   printf("Input your ID: ");
   scanf("%d", &a);

它会起作用.虽然，我不能改变订单，我需要它原样.有人能帮我吗 ?也许我需要使用其他一些功能.谢谢！

It will work. Although, I CANNOT change order and I need it just as-is. Can someone help me ? Maybe I need to use some other functions. Thanks!

推荐答案

尝试:

scanf("%d
", &a);

gets 只读取 scanf 留下的 ' '.另外，你应该使用 fgets 而不是 get:http://www.cplusplus.com/reference/clibrary/cstdio/fgets/ 以避免可能的缓冲区溢出.

gets only reads the ' ' that scanf leaves in. Also, you should use fgets not gets: http://www.cplusplus.com/reference/clibrary/cstdio/fgets/ to avoid possible buffer overflows.

如果上述方法不起作用，请尝试:

if the above doesn't work, try:

...
scanf("%d", &a);
getc(stdin);
...

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