输入C. scanf函数之前得到。问题 [英] Input in C. Scanf before gets. Problem

问题描述

我是pretty新的C，和我有输入查询数据的程序有问题。

I'm pretty new to C, and I have a problem with inputing data to the program.

我的code：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(void) {
   int a;
   char b[20];

   printf("Input your ID: ");
   scanf("%d", &a);

   printf("Input your name: ");
   gets(b);   

   printf("---------");

   printf("Name: %s", b);   

   system("pause");
   return 0;
}

它允许对输入的ID，但它只是跳过输入的其余部分。如果我更改顺序是这样的：

It allows to input ID, but it just skips the rest of the input. If I change the order like this:

printf("Input your name: ");
   gets(b);   

   printf("Input your ID: ");
   scanf("%d", &a);

这会工作。虽然，我不能改变顺序，我需要它只是原样。有人能帮助我吗？也许我需要使用一些其他功能。谢谢！

It will work. Although, I CANNOT change order and I need it just as-is. Can someone help me ? Maybe I need to use some other functions. Thanks!

推荐答案

尝试：

scanf("%d\n", &a);

仅获取读取的'\\ n'在scanf函数叶此外，你应该使用与fgets没有得到：<一href=\"http://www.cplusplus.com/reference/clibrary/cstdio/fgets/\">http://www.cplusplus.com/reference/clibrary/cstdio/fgets/以避免可能的缓冲区溢出。

gets only reads the '\n' that scanf leaves in. Also, you should use fgets not gets: http://www.cplusplus.com/reference/clibrary/cstdio/fgets/ to avoid possible buffer overflows.

编辑：

如果以上不工作，请尝试：

if the above doesn't work, try:

...
scanf("%d", &a);
getc(stdin);
...

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