如何按行号替换文本文件中的整行 [英] How to replace an entire line in a text file by line number

问题描述

我有一种情况，我想要一个 bash 脚本来替换文件中的整行.行号始终相同，因此可以是一个硬编码变量.

I have a situation where I want a bash script to replace an entire line in a file. The line number is always the same, so that can be a hard-coded variable.

我不想替换该行中的某些子字符串，我只想用新行完全替换该行.

I'm not trying to replace some sub-string in that line, I just want to replace that line entirely with a new line.

是否有任何 bash 方法可以执行此操作(或一些可以放入 .sh 脚本的简单方法).

Are there any bash methods for doing this (or something simple that can be thrown into a .sh script).

推荐答案

不是最好的，但应该可以:

Not the greatest, but this should work:

sed -i 'Ns/.*/replacement-line/' file.txt

其中 N 应替换为您的目标行号.这将替换原始文件中的行.要将更改的文本保存在不同的文件中，请删除 -i 选项:

where N should be replaced by your target line number. This replaces the line in the original file. To save the changed text in a different file, drop the -i option:

sed 'Ns/.*/replacement-line/' file.txt > new_file.txt

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