捕获花括号内的内容 [英] Capture contents inside curly braces

问题描述

因此，作为我的应用程序的一部分，我需要它从文本文件中读取数据，并获取大括号之间的元素.

So, as part of my application, I need it to read data from a text file, and get elements between curly brackets.

例如:

Server_1 {

    /directory1 /directory2

}

Server_2 {

    /directory1

    /directory2

}

然后，如果Server == Server_1，则打印目录.

Then something like, if Server == Server_1, print the directories.

推荐答案

你可以试试这个:

{(.*?)}

说明

1. { 匹配字符 { 字面意思(区分大小写)
2. (.*?) 第一个捕获组
3. .*? 匹配任意字符
4. *? 量词——匹配零次和无限次，尽可能少，按需扩展(懒惰)
5. } 字面上匹配字符 }(区分大小写)

1. { matches the character { literally (case sensitive)
2. (.*?) 1st Capturing Group
3. .*? matches any character
4. *? Quantifier — Matches between zero and unlimited times, as few times as possible, expanding as needed (lazy)
5. } matches the character } literally (case sensitive)

提取大括号内内容的示例代码:

Sample Code to extract content inside curly bracket:

 import re

regex = r"{(.*?)}"

test_str = ("Server_1 {
"
    "/directory1 /directory2

"
    "}
"
    "Server_2 {

"
    "/directory1

"
    "/directory2

"
    "}")

matches = re.finditer(regex, test_str, re.MULTILINE | re.DOTALL)

for matchNum, match in enumerate(matches):
    for groupNum in range(0, len(match.groups())):
        print (match.group(1))

在此处运行代码

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