在数据框的列上运行 factor() 时出错 [英] error in running factor() on a column of a data frame

问题描述

我有一个包含多列的数据框.我想在其中一列上运行 factor() 函数，比如名称 my_col.最初我是这样做的

I have a dataframe which has several columns. I want to run the factor() function on one of the columns, say name my_col. Initially I did it this way

df[,"my_col"]<-factor((df[,"my_col"]))

出现以下错误

错误:对于sort.list"，x"必须是原子的清单?

Error: 'x' must be atomic for 'sort.list' Have you called 'sort' on a list?

关于参考 类似问题，所以我的问题解决了.

On referring to a similar question on SO my problem was solved.

现在，如果我尝试以下代码而不是第一种方法，它可以完美运行而不会出现任何错误

Now if instead of the first method I try the following code, it works perfectly without giving any error

df$"my_col"<-factor(df$"my_col")

这是为什么?通过 df$vec_name 和 df[,vec_name] 访问列有区别吗?

Why's that? Is there a difference between accessing a column via df$vec_name and df[,vec_name]?

更新:

str(df)
Classes 'tbl_df', 'tbl' and 'data.frame':   160 obs. of  8 variables:
$ area     : int  1 1 1 1 1 1 1 1 1 1 ...
$ temp     : int  1 1 1 1 1 1 1 1 1 1 ...
$ size     : int  1 1 1 1 1 1 1 1 1 1 ...
$ storage  : int  1 1 1 1 1 2 2 2 2 2 ...
$ my_col   : int  1 2 3 4 5 1 2 3 4 5 ...
$ texture  : num  2.9 2.3 2.5 2.1 1.9 1.8 2.6 3 2.2 2 ...
$ flavor   : num  3.2 2.5 2.8 2.9 2.8 3 3.1 3 3.2 2.8 ...
$ moistness: num  3 2.6 2.8 2.4 2.2 1.7 2.4 2.9 2.5 1.9 ...

推荐答案

你的数据是一个 tbl_df.我没有你的数据，但我们可以看一个使用 mtcars 的例子.

Your data is a tbl_df. I don't have your data, but we can look at an example using mtcars.

library(dplyr)

tbl_df(mtcars)[, "mpg"]
# Source: local data frame [32 x 1]
# 
#      mpg
#    (dbl)
# 1   21.0
# 2   21.0
# 3   22.8
# 4   21.4
# 5   18.7
# 6   18.1
# 7   14.3
# 8   24.4
# 9   22.8
# 10  19.2
# ..   ...

它仍然是一个数据框，而在基数 R 中它会被丢弃到一个原子向量中.dplyr::`[.tbl_df` 不会删除单个列，就像在基础 R 的 [.data.frame 中所做的那样.这就是我们不能运行的原因factor() 就可以了.

It's still a data frame, whereas in base R it would have been dropped to an atomic vector. dplyr:::`[.tbl_df` does not drop single columns, as is done in [.data.frame from base R. This is why we can't run factor() on it.

factor(tbl_df(mtcars)[, "mpg"])
# Error in sort.list(y) : 'x' must be atomic for 'sort.list'
# Have you called 'sort' on a list?

所以你需要使用 [[，就像在 df[["my_col"]] 中一样，或者只使用 $.

So you'll need to use [[, as in df[["my_col"]], or just use $.

df[["my_col"]] <- factor(df[["my_col"]])

注意:当您使用 $ 运算符时，您可以不用在列名周围加上引号.

Note: When you use the $ operator you can do it without the quotes around the column name.

df$my_col <- factor(df$my_col)

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