正则表达式匹配的 Groovy 语法 [英] Groovy syntax for regular expression matching

问题描述

以下 Perl 代码的 Groovy 等价物是什么?

What is the Groovy equivalent of the following Perl code?

my $txt = "abc : groovy : def";
if ($txt =~ / : (.+?) : /) {
  my $match = $1;
  print "MATCH=$match
"; 
  # should print "MATCH=groovy
"
}

我知道有不止一种方法可以做到(包括常规的 Java 方法)——但是什么是Groovy 方法"呢?

I know that there's more than one way to do it (including the regular Java way) - but what is the "Groovy way" of doing it?

这是一种实现方式，但感觉有点笨拙——尤其是数组符号(m[0][1])，感觉有点奇怪.有没有更好的方法呢?如果不是 - 请描述 m[0][1] 背后的逻辑.

This is one way of doing it, but it feels a bit clumsy - especially the array notation (m[0][1]) which feels a bit strange. Is there a better way do it? If not - please describe the logic behind m[0][1].

def txt = "java : groovy : grails"
if ((m = txt =~ / : (.+?) :/)) {
  def match = m[0][1]
  println "MATCH=$match"
}

推荐答案

这是我能实现的与 Perl 代码最接近的匹配:

This was the closest match to the Perl code that I could achieve:

def txt = "abc : groovy : def"
if ((m = txt =~ / : (.+?) : /)) {
  def match = m.group(1)
  println "MATCH=$match"
}

// Prints:
// MATCH=groovy

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