计算Android中两次之间的差异 [英] Calculate Difference between two times in Android

问题描述

我有两个字符串变量，例如 StartTime 和 EndTime.我需要通过用 StartTime 减去 EndTime 来计算 TotalTime.

I have two string variables such as StartTime and EndTime. I need to Calculate the TotalTime by subtracting the EndTime with StartTime.

StartTime 和 EndTime 的格式如下:

The Format of StartTime and EndTime is as like follows:

StartTime = "08:00 AM";
EndTime = "04:00 PM";

以小时和分钟格式表示的总时间.如何在 Android 中计算此值?

TotalTime in Hours and Mins Format. How to calculate this in Android?

推荐答案

试试下面的代码.

//假设时间格式为("hh:mm a")格式

// suppose time format is into ("hh:mm a") format

SimpleDateFormat simpleDateFormat = new SimpleDateFormat("hh:mm a");

date1 = simpleDateFormat.parse("08:00 AM");
date2 = simpleDateFormat.parse("04:00 PM");

long difference = date2.getTime() - date1.getTime(); 
days = (int) (difference / (1000*60*60*24));  
hours = (int) ((difference - (1000*60*60*24*days)) / (1000*60*60)); 
min = (int) (difference - (1000*60*60*24*days) - (1000*60*60*hours)) / (1000*60);
hours = (hours < 0 ? -hours : hours);
Log.i("======= Hours"," :: "+hours);

产出 - 小时 :: 8

这篇关于计算Android中两次之间的差异的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！