计算两次之间的差异android [英] Calculate difference between two times android

问题描述

我正在开发和Android应用程序，我需要计算两次之间的差异。我需要计算24小时的时差，以及两天的时间差异（例如今天下午5点到明天上午9点）

我尝试了以下代码，以计算仅在24小时工作的差异，

  String dateStart =08:00:00; 
 String dateStop =13:00:00; 
 
 // HH以24小时格式转换小时（0-23），日计算
 SimpleDateFormat format = new SimpleDateFormat（HH：mm：ss）; 
 
日期d1 = null; 
日期d2 = null; 
 
 try 
 {
 d1 = format.parse（dateStart）; 
 d2 = format.parse（dateStop）; 
 
 //以毫秒为单位
 long diff = d2.getTime（） -  d1.getTime（）; 
 long diffHours = diff /（60 * 60 * 1000）％24; 
 Log.e（test，diffHours +hours）; 
} 
 catch（异常e）
 {
 // TODO：handle exception 
} 
  

解决方案

主席先生，您可以轻松使用java功能。 long difference = date2.getTime（） - date1.getTime（）; 看看这个链接将帮助您。

I am developing and android app, where I need to calculate the difference between two times.I need to calculate the time difference for 24 hrs, and also the difference between times on two days(Eg. 5pm today to 9 am tomorrow).

I have tried the below code, to calculate the difference which works only for 24 hrs,

String dateStart = "08:00:00";
String dateStop = "13:00:00";

//HH converts hour in 24 hours format (0-23), day calculation
SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");

Date d1 = null;
Date d2 = null;

try 
{
    d1 = format.parse(dateStart);
    d2 = format.parse(dateStop);

    //in milliseconds
    long diff = d2.getTime() - d1.getTime();
    long diffHours = diff / (60 * 60 * 1000) % 24;
    Log.e("test",diffHours + " hours, ");
}
catch (Exception e) 
{
    // TODO: handle exception
} 

解决方案

Sir, you can make it easily in using java feature. long difference = date2.getTime() - date1.getTime(); Take a look in this link this will help you.

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