将 BeautifulSoup 元素解析为 Selenium [英] Parse BeautifulSoup element into Selenium

问题描述

我想获取一个使用selenium的网站的源代码；使用 BeautifulSoup 查找特定元素；然后将其作为 selenium.webdriver.remote.webelement 对象解析回 selenium.像这样:

I want to get the source code of a website using selenium; find a particular element using BeautifulSoup; and then parse it back into selenium as a selenium.webdriver.remote.webelement object. Like so:

driver.get("www.google.com")
soup = BeautifulSoup(driver.source)
element = soup.find(title="Search")

element = Selenium.webelement(element)
element.click()

我怎样才能做到这一点?

How can I achieve this?

推荐答案

对我有用的通用解决方案是计算 bs4 元素的 xpath，然后用它来查找 selenium 中的元素，

A general solution that worked for me is to compute the xpath of the bs4 element, then use that to find the element in selenium,

xpath = xpath_soup(soup_element)
selenium_element = driver.find_element_by_xpath(xpath)

...

import itertools

def xpath_soup(element):
    """
    Generate xpath of soup element
    :param element: bs4 text or node
    :return: xpath as string
    """
    components = []
    child = element if element.name else element.parent
    for parent in child.parents:
        """
        @type parent: bs4.element.Tag
        """
        previous = itertools.islice(parent.children, 0, parent.contents.index(child))
        xpath_tag = child.name
        xpath_index = sum(1 for i in previous if i.name == xpath_tag) + 1
        components.append(xpath_tag if xpath_index == 1 else '%s[%d]' % (xpath_tag, xpath_index))
        child = parent
    components.reverse()
    return '/%s' % '/'.join(components)

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