使用 BeautifulSoup 在 Python 中查找非递归 DOM 子节点 [英] Finding a nonrecursive DOM subnode in Python using BeautifulSoup

问题描述

有没有办法在 Python 中使用 BeautifulSoup 找到非递归 DOM 子节点?

Is there any way to find a nonrecursive DOM subnode in Python using BeautifulSoup?

例如考虑解析一个 pom.xml 文件:

E.g. consider parsing a pom.xml file:

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">

    <parent>
        <groupId>com.parent</groupId>
        <artifactId>parent</artifactId>
        <version>1.0-SNAPSHOT</version>
        <relativePath>../pom.xml</relativePath>
    </parent>

    <modelVersion>2.0.0</modelVersion>
    <groupId>com.parent.somemodule</groupId>
    <artifactId>some_module</artifactId>
    <packaging>jar</packaging>
    <version>1.0-SNAPSHOT</version>
    <name>Some Module</name>
    ...

如果我想在顶层获得 groupId(特别是 project->groupId，而不是 project->parent->groupId代码>)，我使用:

If I want to get groupId at the top level (specifically project->groupId, not project->parent->groupId), I use:

with open(pom) as pomHandle:
    soup = BeautifulSoup(pomHandle)

groupId = soup.groupid.text

但不幸的是，它会在文件中找到 groupId 的第一个物理出现，而不管层次结构级别，即 project->parent->groupId.我实际上只想在特定节点级别而不是在其子节点中进行非递归查找.有没有办法在 BeautifulSoup 中做到这一点?

But unfortunately, that finds the first physical occurrence of groupId in the file regardless of the hierarchy level, which is project->parent->groupId. I actually want to do a unrecursive find ONLY at a specific node level, not within its children. Is there a way to do it in BeautifulSoup?

推荐答案

您可以使用 recursive=False 在项目"节点内搜索:

You can search inside "project" node with recursive=False:

groupId = soup.project.find('groupid', recursive=False).text

希望有所帮助.

这篇关于使用 BeautifulSoup 在 Python 中查找非递归 DOM 子节点的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！