使用 BeautifulSoup 获取属性值 [英] Getting attribute's value using BeautifulSoup
本文介绍了使用 BeautifulSoup 获取属性值的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我正在编写一个 python 脚本，它将在从网页解析后提取脚本位置.假设有两种情况:
I'm writing a python script which will extract the script locations after parsing from a webpage. Lets say there are two scenarios :
<script type="text/javascript" src="http://example.com/something.js"></script>
和
<script>some JS</script>
我可以从第二个场景中获取 JS，也就是将 JS 写入标签中.
I'm able to get the JS from the second scenario, that is when the JS is written within the tags.
但是有什么办法，我可以从第一个场景中获取 src 的值(即提取脚本中 src 标签的所有值，例如 http://example.com/something.js)
But is there any way, I could get the value of src from the first scenario (i.e extracting all the values of src tags within script such as http://example.com/something.js)
这是我的代码
#!/usr/bin/python
import requests
from bs4 import BeautifulSoup
r = requests.get("http://rediff.com/")
data = r.text
soup = BeautifulSoup(data)
for n in soup.find_all('script'):
print n
输出:一些JS
需要的输出:http://example.com/something.js
推荐答案
仅当 src 值存在时，它才会获取所有的值.否则它会跳过那个
