使用BeautifulSoup获取基于name属性的属性值 [英] Get an attribute value based on the name attribute with BeautifulSoup

问题描述

我想根据属性名称打印属性值，例如

I want to print an attribute value based on its name, take for example

<META NAME="City" content="Austin">

我想做这样的事情

soup = BeautifulSoup(f)  # f is some HTML containing the above meta tag
for meta_tag in soup("meta"):
    if meta_tag["name"] == "City":
        print(meta_tag["content"])

上面的代码给出了一个 KeyError:'name'，我相信这是因为BeatifulSoup使用了name，因此它不能用作关键字参数.

The above code give a KeyError: 'name', I believe this is because name is used by BeatifulSoup so it can't be used as a keyword argument.

推荐答案

这很简单，请使用以下命令-

It's pretty simple, use the following -

>>> from bs4 import BeautifulSoup
>>> soup = BeautifulSoup('<META NAME="City" content="Austin">')
>>> soup.find("meta", {"name":"City"})
<meta name="City" content="Austin" />
>>> soup.find("meta", {"name":"City"})['content']
u'Austin'

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