如何在匹配后仅显示下一行? [英] How to show only next line after the matched one?

问题描述

grep -A1 'blah' logfile

多亏了这个命令，每一行都有 'blah' ，我得到了包含 'blah' 的行的输出以及日志文件中的下一行.这可能是一个简单的方法，但我找不到一种方法来省略具有 'blah' 和 only 在输出中显示下一行的行.

Thanks to this command for every line that has 'blah' in it, I get the output of the line that contains 'blah' and the next line that follows in the logfile. It might be a simple one but I can't find a way to omit the line that has 'blah' and only show next line in the output.

推荐答案

你可以用awk试试:

awk '/blah/{getline; print}' logfile

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