如何在匹配的后面显示下一行？ [英] How to show only next line after the matched one?

问题描述

  grep -A1'blah'日志文件
  

感谢这个命令对于每一行有'blah'的行，我得到包含'blah'的行的输出以及日志文件中后面的下一行。这可能是一个简单的方法，但我无法找到一种方法来省略只有'blah'和 显示输出中下一行的行。

  awk'/ blah / {函数getline; print}'logfile 
  

grep -A1 'blah' logfile

Thanks to this command for every line that has 'blah' in it, I get the output of the line that contains 'blah' and the next line that follows in the logfile. It might be a simple one but I can't find a way to omit the line that has 'blah' and only show next line in the output.

解决方案

you can try with awk:

awk '/blah/{getline; print}' logfile

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