Linux bash脚本提取IP地址 [英] Linux bash script to extract IP address

问题描述

我想在我的 Debian 7.3 上制作大脚本(类似翻译和更新的用户友好环境).我有个问题.我只想使用命令给我的一些信息.例如我的 ifconfig 看起来像:

I want to make big script on my Debian 7.3 ( something like translated and much more new user friendly enviroment ). I have a problem. I want to use only some of the informations that commands give me. For example my ifconfig looks like:

eth0      Link encap:Ethernet  HWaddr 08:00:27:a3:e3:b0  
          inet addr:192.168.1.103  Bcast:192.168.1.255  Mask:255.255.255.0
          inet6 addr: fe80::a00:27ff:fea3:e3b0/64 Scope:Link
          UP BROADCAST RUNNING MULTICAST  MTU:1500  Metric:1
          RX packets:1904 errors:0 dropped:0 overruns:0 frame:0
          TX packets:2002 errors:0 dropped:0 overruns:0 carrier:0
          collisions:0 txqueuelen:1000 
          RX bytes:1309425 (1.2 MiB)  T

我只想在行中显示 IP 地址:echo "Your IP address is: (IP_ADDRESS)".是否有任何命令可以让我做这样的事情，在流中搜索我想要获取的信息?.我知道 grep 和 sed 但我对它们并不擅长.

I want to display only the IP address in line: echo "Your IP address is: (IP_ADDRESS )". Is there any command that allow me to do such a thing, to search in stream for informations I want to get?. I know about grep and sed but I am not really good with them.

首先感谢您帮助我解决这个问题，现在我知道的更多了.其次说项目在进行中.如果有人对它感兴趣，请pm我.

Firstly to say thank you for helping me with this problem, now I know much more. Secondly to say project is in progress. If anyone would be interested in it just pm me.

推荐答案

只需获取您的 IP 地址:

To just get your IP address:

echo `ifconfig eth0 2>/dev/null|awk '/inet addr:/ {print $2}'|sed 's/addr://'`

这会给你 eth0 的 IP 地址.

This will give you the IP address of eth0.

由于最近版本的 Ubuntu 中接口的名称更改，这不再起作用.相反，你可以使用这个:

Due to name changes of interfaces in recent versions of Ubuntu, this doesn't work anymore. Instead, you could just use this:

hostname --all-ip-addresses 或 hostname -I，它们做同样的事情(给你主机的所有 IP 地址).

hostname --all-ip-addresses or hostname -I, which does the same thing (gives you ALL IP addresses of the host).

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