如何在 sed 中匹配多个地址? [英] How do I match multiple addresses in sed?

问题描述

我想对与多个命令的 and 或 or 匹配的任何行执行一些 sed 命令:例如，sed '50,70/abc/d' 将删除 50,70 范围内与 /abc/ 匹配的所有行，或执行 的方法>sed -e '10,20s/complicated/regex/' -e '30,40s/complicated/regex/ 无需重新输入 s/compicated/regex/

I want to execute some sed command for any line that matches either the and or or of multiple commands: e.g., sed '50,70/abc/d' would delete all lines in range 50,70 that match /abc/, or a way to do sed -e '10,20s/complicated/regex/' -e '30,40s/complicated/regex/ without having to retype s/compicated/regex/

推荐答案

Logical-and

和部分可以用大括号完成:

Logical-and

The and part can be done with braces:

sed '50,70{/abc/d;}'

此外，可以为多个和条件嵌套大括号.

Further, braces can be nested for multiple and conditions.

(以上是在 GNU sed 下测试的.BSD sed 可能在小但令人沮丧的细节上有所不同.)

(The above was tested under GNU sed. BSD sed may differ in small but frustrating details.)

or 部分可以用分支处理:

The or part can be handled with branching:

sed -e '10,20{b cr;}' -e '30,40{b cr;}' -e b -e :cr -e 's/complicated/regex/' file

• 10,20{b cr;}

  对于从 10 到 20 的所有行，我们分支到标签 cr

  For all lines from 10 through 20, we branch to label cr

  30,40{b cr;}

  对于从 30 到 40 的所有行，我们分支到标签 cr

  For all lines from 30 through 40, we branch to label cr

  b

  对于所有其他行，我们跳过其余的命令.

  For all other lines, we skip the rest of the commands.

  :cr

  这标志着标签cr

  s/complicated/regex/

  这对分支到 cr 的行执行替换.

  This performs the substitution on lines which branched to cr.

  使用 GNU sed，上述语法可以稍微缩短为:

  With GNU sed, the syntax for the above can be shortened a bit to:

  sed '10,20{b cr}; 30,40{b cr}; b; :cr; s/complicated/regex/' file
  

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