如何删除bash输出中的装饰颜色字符? [英] How to remove the decorate colors characters in bash output?

问题描述

控制台程序 (translate-shell) 有一个带有颜色的输出，并为此使用特殊的装饰字符:^[[22m, ^[[24m, ^[[1m... 等等.

A console program (translate-shell) has an output with colors and uses special decorate characters for this: ^[[22m, ^[[24m, ^[[1m... and so on.

我想删除它们以获得纯文本.

I'd like to remove them to get a plain text.

我尝试使用 tr -d "^[[22m" 和 sed 's/[^[[22m]//g'，但只删除了数字，而不是特殊字符 ^[

I tried with tr -d "^[[22m" and with sed 's/[^[[22m]//g', but only is removed the number, not the special character ^[

谢谢.

推荐答案

您有多种选择:

• https://unix.stackexchange.com/questions/14684/removing-control-chars-including-console-codes-colours-from-script-output
• http://www.commandlinefu.com/commands/view/3584/remove-color-codes-special-characters-with-sed
• 以及 Jens 在其他答案中指出的 -no-ansi

编辑

来自commandlinefu的解决方案 做得很好:

sed -r "s/x1B[([0-9]{1,2}(;[0-9]{1,2})?)?[m|K]//g"

来自 unix.stackexchange 的解决方案 可能更好，但要长得多，因此您需要创建一个单独的脚本文件，因为它太长了，而不仅仅是做一个 shell 单行.

The solution from unix.stackexchange might be better but is much longer and so you would want to create a separate script file because it is so long instead of just doing a shell one-liner.

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