如何清除bash输出中的装饰颜色字符？ [英] How to remove the decorate colors characters in bash output?

问题描述

一个控制台程序（translate-shell）有一个颜色输出，并为此使用特殊的装饰字符：^ [[22m，^ [[24m，^ [[1m ...等等。

$

我尝试使用tr -d^ [[22m和带有sed的/ [\ ^ [[22m] // g'，但只删除数字，而不是特殊字符^ [

谢谢。 / p>

解决方案

您有多种选择：

• https://unix.stackexchange.com / questions / 14684 / removal-control-chars-including-console-codes-colors-from-script-output


• http://www.commandlinefu.com/commands/view/3584/remove-color- code-special-characters-with-sed


• 和 -no-ansi 回答

EDIT

工作相当不错：

  sed -rs / \x1B\ [（[0-9] {1， 2}（; [0-9] {1,2}）？）？[m | K] // g
  

A console program (translate-shell) has an output with colors and uses special decorate characters for this: ^[[22m, ^[[24m, ^[[1m... and so on.

I'd like to remove them to get a plain text.

I tried with tr -d "^[[22m" and with sed 's/[\^[[22m]//g', but only is removed the number, not the special character ^[

Thanks.

解决方案

You have multiple options:

• https://unix.stackexchange.com/questions/14684/removing-control-chars-including-console-codes-colours-from-script-output
• http://www.commandlinefu.com/commands/view/3584/remove-color-codes-special-characters-with-sed
• and as -no-ansi as pointed out by Jens in other answer

EDIT

This command does the job pretty well:

sed -r "s/\x1B\[([0-9]{1,2}(;[0-9]{1,2})?)?[m|K]//g"

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