Android - 从 getView() 中删除 GridView 项目? [英] Android - Remove GridView item from inside getView()?

问题描述

我需要一种从 GridView 中删除项目的方法，但这必须在我的自定义适配器内的 getView() 方法中完成.这是我的 GridView:

I need a way to remove an Item from the GridView but this must be done from within the getView() method inside my custom Adapter. Here is my GridView:

活动:

    ...
    String[] newList;
    newList[0] = "Item 1";
    newList[1] = "Item 2";
    newList[2] = "Item 3";
    ...
    GridView GV = (GridView) getActivity().findViewById(R.id.gv);
    GV.setAdapter(new Adapter(getActivity(), newList));
    GV.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView arg0, 
            View arg1, int position, long arg3) {
            ...
        }
    });

适配器

public class Adapter extends BaseAdapter {

    private Context mContext;
    private LayoutInflater mInflator;
    private String mEntries[];

    public static class ViewHolder {
        public TextView myTextView;
    }

    public Adapter (Context context, String[] entries) {
        mContext = context;
        mInflator = (LayoutInflater) mContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        mEntries = entries; 
    }

    @Override
    public int getCount() {
        return mEntries.length;
    }

    @Override
    public Object getItem(int position) {
        return position;
    }

    @Override
    public long getItemId(int position) {
        return position;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {

        ViewHolder holder = null;
        if(convertView == null) {
            convertView = mInflator.inflate(R.layout.gvitemlayout, parent, false);
            holder = new ViewHolder();
            holder.myTextView = (TextView) convertView.findViewById(R.list.removeItem);
            convertView.setTag(holder);
        } else {
            holder = (ViewHolder) convertView.getTag();
        }

        String string = mEntries[position];
        String[] data = string.split("\.");

        if (data.length < 2) {
            TextView itemName = (TextView) convertView.findViewById(R.list.itemName);
            itemName.setText("");
            TextView itemClass = (TextView) convertView.findViewById(R.favlist.itemClass);
            itemClass.setText("");
            holder.myTextView.setText("");
            TextView itemNone = (TextView) convertView.findViewById(R.list.itemNone);
            itemNone.setText("No Items");
        } else {
            TextView itemName = (TextView) convertView.findViewById(R.list.itemName);
            itemName.setText(data[1]);
            TextView itemClass = (TextView) convertView.findViewById(R.list.itemClass);
            itemClass.setText(data[0]);
        }

        final int info = (Integer) getItem(position);
        holder.myTextView.setOnClickListener(new OnClickListener() {
            public void onClick(View v) {               
                SharedPreferences sP = mContext.getSharedPreferences("fav", mContext.MODE_PRIVATE);
                Boolean b = sP.getBoolean(mEntries[info], false);
                if (b == true) {
                    SharedPreferences.Editor editor = sP.edit();
                    editor.remove(mEntries[info]);
                    editor.commit();

                    // REMOVE ITEM CODE NEEDED HERE

                }
            }
        });
        return convertView;
    }
}

希望这能让我更容易理解我的需求.

Hope this makes it easier to understand what I need.

推荐答案

这就是我所做的，不需要初始化 'adapter' 变量.在 getView() 中，只需执行以下操作:

This is what I did, there was no need to initialise the 'adapter' variable. Inside the getView() simply do this:

1. 从列表中删除用作数据源的项目.

所以.如果您想从列表中删除第 2 项

So. if you want to remove Item 2 from the list

String mEntries[] = ITEM1、ITEM2、ITEM3 等

这样做:

String newList[] = new String[mEntries.length - 1]; 
int count = 0;
for (int i = 0; i < mEntries.length; i++) {
    if (mEntries.length - 1 > 0) {
        if (mEntries[i] == mEntries[1]) { // mEntries[1] as the range starts from 0, so 1 would be ITEM2
            // SKIP IF MATCHES THE ITEM YO WANT TO REMOVE                       
        } else {
            newList[count] = mEntries[i];
            count++;
        }
    }
}
mEntries = newList; // save the new list into mEntries
notifyDataSetChanged(); // notify the changes and the listview/gridview will update

这篇关于Android - 从 getView() 中删除 GridView 项目?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！