如何在 JUnit 中获取 src/test/resources 目录的路径? [英] How to get the path of src/test/resources directory in JUnit?

问题描述

我知道我可以从 src/test/resources 加载一个文件:

I know I can load a file from src/test/resources with:

getClass().getResource("somefile").getFile()

但是如何获取src/test/resources目录的完整路径，即我不想加载文件，我只想知道目录的路径?

But how can I get the full path to the src/test/resources directory, i.e. I don't want to load a file, I just want to know the path of the directory?

推荐答案

尝试使用 ClassLoader 类:

ClassLoader classLoader = getClass().getClassLoader();
File file = new File(classLoader.getResource("somefile").getFile());
System.out.println(file.getAbsolutePath());

A ClassLoader 负责加载类.每个类都有一个对 ClassLoader 的引用.此代码从资源目录返回一个 File.对其调用 getAbsolutePath() 返回其绝对Path.

A ClassLoader is responsible for loading in classes. Every class has a reference to a ClassLoader. This code returns a File from the resource directory. Calling getAbsolutePath() on it returns its absolute Path.

ClassLoader 的 Javadoc:http://docs.oracle.com/javase/7/docs/api/java/lang/ClassLoader.html

Javadoc for ClassLoader: http://docs.oracle.com/javase/7/docs/api/java/lang/ClassLoader.html

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