Python:如何比较字符串并忽略空格和特殊字符 [英] Python : How to compare strings and ignore white space and special characters

问题描述

我想比较两个字符串，以便比较时忽略特殊字符的差异.也就是说，

I want to compare two strings such that the comparison should ignore differences in the special characters. That is,

嘿，这是一个测试

应该匹配

喂！这是一个测试或"这是一个测试

Hai ! this is a test "or" Hai this is a test

有没有办法在不修改原始字符串的情况下做到这一点?

Is there any way to do this without modifying the original strings?

推荐答案

这会在进行比较之前删除标点符号和空格:

This removes punctuation and whitespace before doing the comparison:

In [32]: import string

In [33]: def compare(s1, s2):
    ...:     remove = string.punctuation + string.whitespace
    ...:     return s1.translate(None, remove) == s2.translate(None, remove)

In [34]: compare('Hai, this is a test', 'Hai ! this is a test')
Out[34]: True

这篇关于Python:如何比较字符串并忽略空格和特殊字符的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！