如何比较字符串和整数在python？ [英] How to compare string and integer in python?

问题描述

我有这个简单的python程序。我运行它，它打印是，实际上我希望它不打印任何东西，因为 14 不大于 14 。

I have this simple python program. I ran it and it prints yes, when in fact I expect it to not print anything because 14 is not greater than 14.

我看到了这个相关问题，但它不是很有帮助。

I saw this related question, but it isn't very helpful.

#! /usr/bin/python

import sys

hours = "14"

if (hours > 14):
        print "yes"

我做错了什么？

推荐答案

将字符串转换为整数 int ：

hours = int("14")

if (hours > 14):
        print "yes"

在CPython2中，当比较两个不同类型的非数值对象时，比较是通过比较类型。由于'int'< 'string'，任何int小于任何字符串

In CPython2, when comparing two non-numerical objects of different types, the comparison is performed by comparing the names of the types. Since 'int' < 'string', any int is less than any string.

In [79]: "14" > 14
Out[79]: True

In [80]: 14 > 14
Out[80]: False

这是一个经典的Python陷阱。在Python3中，这个疣已被更正 - 比较不同类型的非数值对象默认会引起TypeError。

This is a classic Python pitfall. In Python3 this wart has been corrected -- comparing non-numerical objects of different type raises a TypeError by default.

As 展示在文档中：

CPython实现细节：不同类型的对象（
除外）按照类型名称排序;对不支持正确比较的相同类型
的对象按其地址排序。

CPython implementation detail: Objects of different types except numbers are ordered by their type names; objects of the same types that don’t support proper comparison are ordered by their address.

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