如何在Python中比较字符串和整数？ [英] How do I compare a string and an integer in Python?

问题描述

我是Python的新手。
我写了这个，当我在输入中输入一个字母时出现了这个错误：

I am quite a newbie in Python. I wrote this and got this error when i typed a letter in the input:

TypeError: unorderable types: str() >= int()

这是我写的代码：

user_input = input('How old are you?: ')
if user_input >= 18:
   print('You are an adult')
elif user_input < 18:
     print('You are quite young')
elif user_input == str():
     print ('That is not a number')

推荐答案

你应该这样做：

user_input = int(input('How old are you?: '))

因此，当您明确地将输入转换为int时，它总是会尝试将输入转换为整数，并在输入字符串而不是int时引发 valueError 。要处理这些情况，请执行以下操作：

so as you explicitly cast your input as int, it will always try to convert the input into an integer, and will raise a valueError when you enter a string rather than an int. To handle those cases, do:

except ValueError:
    print ('That is not a number')

因此，完整的解决方案可能如下所示：

So, the full solution might be like below:

try:
    user_input = int(input('How old are you?: '))

    if user_input >= 18:
         print('You are an adult')
    else:
         print('You are quite young')
except ValueError:
    print ('That is not a number')

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