当 fopen() 失败时获取有意义的信息 (PHP/suPHP) [英] Get meaningful information when fopen() fails (PHP/suPHP)

问题描述

当我无法打开文件时，如何获得比FALSE"更有意义的信息.

How do I get something more meaningful than 'FALSE' when I can't open a file.

$myFile = "/home/user/testFile.txt"; 
$fh = fopen($myFile, 'w') or die("can't open file");

当我使用die语句时，can't open file返回给客户端，几乎没用.如果我删除它，则不会引发任何错误.如果我返回 $fh，它是 FALSE.我尝试了本地文件名和绝对文件名.我的 index.html 文件位于我的hole 文件夹的子文件夹之一中.此外，我将 suPHP 与我试图写入的文件夹一起使用，以获得 0755 的权限(suPHP 要求所有文件夹都使用此权限).

When I use the die statement, can't open file is returned to the client, and it is almost useless. If I remove it, no error is raised. If I return $fh it is FALSE. I tried both local file name and absolute file name. My index.html file is in one of the sub folders of my hole folder. Furthermore, I am using suPHP with the folder I am trying to write to having a permission of 0755 (suPHP requires this for all folders).

我如何找出出现问题的原因，或者至少在尝试打开文件之前查询它.

How do I figure out why there was a problem, or at least query it before trying to open the file.

推荐答案

fopen 如果失败，应该引发 E_WARNING.请参阅 error_get_last 或 set_error_handler(*) 来捕捉它.除此之外，您可以使用 file_exists 和 is_readable 以检查文件是否丢失或存在其他(可能与权限相关的)问题.

fopen should raise an E_WARNING if it fails. See error_get_last or set_error_handler(*) to catch it. Other than that you can use file_exists and is_readable to check whether the file is missing or there's another (probably permission-related) problem.

(*) 我认为始终设置一个将所有 PHP 错误转换为异常的错误处理程序是一种很好的做法.

(*) I consider it good practice to always set an error handler that turns all PHP errors into exceptions.

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